0=18x^2-54x-324

Solution for 0=18x^2-54x-324 equation:

0=18x^2-54x-324

We move all terms to the left:

0-(18x^2-54x-324)=0

We add all the numbers together, and all the variables

-(18x^2-54x-324)=0

We get rid of parentheses

-18x^2+54x+324=0

a = -18; b = 54; c = +324;
Δ = b2-4ac
Δ = 542-4·(-18)·324
Δ = 26244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26244}=162$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-162}{2*-18}=\frac{-216}{-36}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+162}{2*-18}=\frac{108}{-36}
=-3
$